The principal organic product formed in the reaction given below is
$CH_2 = CH(CH_2)_8COOH + HBr \xrightarrow{\text{peroxide}} ....$

  • A
    $CH_3-CHBr(CH_2)_8COOH$
  • B
    $CH_2 = CH(CH_2)_8COBr$
  • C
    $BrCH_2-CH_2(CH_2)_8COOH$
  • D
    $CH_2 = CH(CH_2)_7CHBrCOOH$

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